Question

find the smaller value of y that satisfies the equation y^2 + 2y = 35

Answer 1

y^2 + 2y - 35 = 0

y^2 + 7y - 5y - 35 = 0

y(y + 7) - 5(y + 7) = 0

(y-5)(y+7) = 0

y = 5, -7

Smaller value: -7