Question

find the smalles square no. which is divisible by each of the numbers 4,18 and 21 plz answer fast very urgent​

Answer 1

Answer

Take the LCM of 4,18,21

2|4,18,21

2|2,9,21

2|1,9,21

3|1,3,7

3|1,1,7

7|1,1,1

LCM =2*2*2*3*3*7

=504

We need to complete the pairs of prime in even so we need to multiply the number by 2and 7

The number is 504*2*7=7056

The number 7056 is square of 84

Answer 2

Answer:

1764

Step-by-step explanation:

Lcm of 4,18,21 is 2×2×3×3×7= 252

7 is not in pair, so we will multiply 252 by 7 to make it perfect square no.

252×7=1764

Therefore,1764 is the smallest square no. divisible by 4,18,21

Hope it helps