find the smallest 3 digit number which is divisible by 18,24 and 32
Answers
Answered by
0
Answer:
xxcyycyycyycycyxxuoxggzlTyyuucbbyyyy
Answered by
0
Answer:
102
Step-by-step explanation:
The smallest three digit number is 100.
Now, HCF of 18, 24 and 32;
18 = 2×3²
24 = 2³x3
32 = 2⁵
Therefore,
HCF = product of common factors
= 2
Hence, the smallest three digit number which is divisible by 18, 24 and 32 is:-
(100+2) = 102
Similar questions