find the smallest 3 digit number which when increased by 5 is divisible by 48, 32 and 24.
Answers
Answered by
15
first take the lcm of 48,32,24
which is 96
but this is not a three digit number
so just add 96+96
192
so now just subtract 5 from it
which 187
number is 187
which is 96
but this is not a three digit number
so just add 96+96
192
so now just subtract 5 from it
which 187
number is 187
fiercespartan:
mine as the brainliest
Answered by
7
Take the LCM of 48,32 and 24
which will be 96
now multiply it by 2 192
now 192-5=187 is your answer
which will be 96
now multiply it by 2 192
now 192-5=187 is your answer
plz brainliest
me brainliest
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