Question

Find the smallest 4 digit no. divisible by 18, 24, 32.

Answer 1

Answer:

hey , your answer in this image---------

Answer 2

Step-by-step explanation:

L.C.M of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 =288 The smallest four-digit number = 1000 Now, Therefore, the required number is 1000+(288-136)=1152

LCM of 18, 24 and 32:

OR,

18 = 2 x 3 x 3

24 = 2 x 2 x 2 x 3

32 = 2 x 2 x 2 x 2 x 2

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288

The smallest four digit number that is divisible by 288:

288 x 3 = 864

288 x 4 = 1152

Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.

Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32