Math, asked by padhiamarendra1954, 10 months ago

find the smallest 4 digit number divisible by 18 24 and 32​

Answers

Answered by atharva4810
0

Answer:

1152 is the smallest number divisible by 18, 24 and 32.

Pls mark me as brainliest

Answered by rakhister80
1

Answer:

1,152

Step-by-step explanation:

L.C.M of 18→ 2×3×3

L.C.M of 24→2×2×2×3

L.C.M of 32→2×2×2×2×2

L.C.M of 18,24&32≈2×2×2×2×2×3×3≈288

Now we have to multiple 288×4 because we have to find the smallest 4-digit number.

288×4≈1,152

So the smallest 4-digit number which is divisible by 18,24&32 is 1,152.

Similar questions