find the smallest 4 digit number divisible by 18 24 and 32
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Answered by
0
Answer:
1152 is the smallest number divisible by 18, 24 and 32.
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Answered by
1
Answer:
1,152
Step-by-step explanation:
L.C.M of 18→ 2×3×3
L.C.M of 24→2×2×2×3
L.C.M of 32→2×2×2×2×2
L.C.M of 18,24&32≈2×2×2×2×2×3×3≈288
Now we have to multiple 288×4 because we have to find the smallest 4-digit number.
288×4≈1,152
So the smallest 4-digit number which is divisible by 18,24&32 is 1,152.
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