Find the smallest 4 digit number such that when divided by 12 18 21 and 28 is leave the remainder 3 in each case
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Find the prime factors:
12 = 2² x 3
18 = 2 x 3²
21 = 3 x 7
28 = 2² x 7
Find the LCM:
LCM = 2² x 3² x 7 = 252
Find the smallest 4 digit number that is a multiples of 252:
Smallest 4 digit number = 1000
1000 ÷ 252 = 3.97 ≈ 4 (round up)
smallest 4 digit number that is a multiples of 252 = 252 x 4 = 1008
It has a reminder of 3
⇒ The number is 1008 + 3 = 1011
Answer: The number is 1011
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