Math, asked by jamrosh, 11 months ago

find the smallest 4 digit number such that when it is divided by 12,18,21 and 28.it leaves remainder 3 in each case

Answers

Answered by gautamkumar77

4

Answer:

1011

Step-by-step explanation:

LCM =12,18,21and 28

LCM = 252

252 se 1000 m divided kare

to 1000/252

remainder 244

1000+(252-244)

1000+8=1008

remainder 3 add kare

1008+3=1011

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