Question

find the smallest 4 digit number such that when it is divided by 12,
18, 21 and 28. it leave remainder 3 in each case.
Oa. 1101
Ob. 1000
OC. 1011
d. 1110​

Answer 1

Answer:

1011.

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Answer 2

Step-by-step explanation:

The smallest number divisible by any given numbers is the lcm of that/or those numbers and for 4 digit numbers we can simply multiply the lcm till we acquire 4 digit number. The remainder is the number to be added to the lcm.

Thus

LCM of 12,18,21 and 28

=252

so the 4 digit number will be

252×4

=1008

so, adding the remainder we have

1008+3 = 1011