Find the smallest 4-digit number which divided by 6, 15 and 18 leave remainder 5 in each case.
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Answer:
95
Step-by-step explanation:
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.
Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Let us check our answer.
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore the required number = 90+5=95
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