Question

Find the smallest 4 digit number which is divisible by 18 20 32​

Answer 1

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Smallest number divisible by 18,24,32

Factors of 18=2×3×3

Factors of 20=2×2×5

Factors of 32=2×2×2×2×2

LCM=2×2×2×2×3×5=240

∴240 is the smallest number divisible by 18,20,32

Now, smallest 4 digit number=1000

1000=240×4+40

Remainder=40

But we need to find a number where the remainder is 0

Required number=1000+(240−40)=1000+200=1200

So,1200 is the smallest 4 digit number.

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