Question

find the smallest 4 digit number which is divisible by 18, 24 and 32

also mention how you got the answer

Answer 1

the smallest 4 digits number which is divisible by 18 , 24 and 32 . A multiply of the LCM given number is 18 , 24 and 32 .
18 , 24 ,32= 2 x 2 x2 x2 x 2 x 3 x 3 = 288
required smallest 4 digit number is 4x 288 = 1152.

hope it's help u

Answer 2

the answer is= ( 1152 )