Question

Find the smallest 4-digit number which is divisible by 18, 24 and 32​

Answer 1

Answer:

I think 1000 is the right answer for this question

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Answer 2

Answer:

Step-by-step explanation:

Largest 4 digit number= 9999

H.C.F. of 18, 24 and 32

18= 2×3×3

24=2×2×2×3

32=2×2×2×2×2

∴ H.C.F. = 2

∴ 9999÷2 gives the remainder 1

∴9999-1

=9998

The number 9998 is the required numbered.

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