Find the smallest 4 digit number which is divisible by 6 , 15 and leave remainder 5 in each case
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Step-by-step explanation:
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case. Let us check our answer.
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