Question

find the smallest 4 - digit number which is divisible by 8, 18 and 24​

Answer 1

Answer:

Smallest number divisible by 18,24,32

Factors of 18=2×3×3

Factors of 24=2×3×2×2

Factors of 32=2×2×2×2×2

LCM=2×2×2×2×2×3×3=288

∴288 is the smallest number divisible by 18,24,32

Now, smallest 4 digit number=1000

1000=288×3+136

Remainder=136

But we need to find a number where the remainder is 0

Required number=1000+(288−136)=1000+152=1152

So,1152 is the smallest 4 digit number.

Answer 2

Answer:

1536 is the smallest 4 digit number divisible by 8,18,24.