Math, asked by srikutty44, 8 months ago

find the smallest 4digit weather the number divisible by 18 24 and 32​

Answers

Answered by aditin88
3

Answer:

Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers. Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.

Step-by-step explanation:

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Answered by Anonymous
0

Answer:

1152 is the smallest 4 digit no divisible by 18,24 and 32

Step-by-step explanation:

Prime factors of 18,24 and 32 are

18=2*3²

24=2³*3

32=2^5

Thus LCM (18,24,32)=2^5*3²=32*9=288

Now smallest 4 digit no=1000

and 1000=288*3+136

The smallest 4 digit no should be multiple of 288

Now next multiple of 288 is 288*4=1152

Thus 1152 is the smallest 4 digit no divisible by 18,24 and 32

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