Question

Find the smallest 5 digit no. Exactly divisible by 31

Answer 1

The smallest five digit no which is divisible by 31 is exactly equal to 10010

Answer 2

Answer:

10013 is the number which is exactly divisible by 31.

Step-by-step explanation:

Explanation:

10000 is the smallest 5 digit number .

Now divide the 5 digit number 10000 by 31

On dividing 10000 by 31 we get  322 as quotient and 18 as remainder .

So, subtract the remainder by divisor  we get ,

⇒ (31 - 18) = 13

When we added 13 in 10000 then it is exactly divisible by 31.

So , the number is 10013.

Final answer :

Hence , the number is 10013 which is exactly divisible by 31 .