find the smallest 5 digit no. which is divisible by 18,24,32
those who will give right answer i will mark brainliest
explain it whole
Answers
Answered by
4
Answer:
✓First Step : Find LCM of 18, 24, 32
18= 2×3×3
24= 2×2×2×3
32= 2×2×2×2×2
LCM = 288
✓✓Second Step: Note the least Number of 5 Digit
It's 10000
✓✓✓Third step: Find remainder for division 10000/288
It's 208
✓✓✓✓Fourth Step: Required No. = Least 5 Digit Number + (LCM-Remainder)
=> 10000+(288-208)
=> 10000+ 80
=> 10080
This is the required Number
Hope it Helps ☺️
Answered by
2
Answer:
Step-by-step explanation:
answer is given down with attachment
Attachments:
Similar questions