Question

find the smallest 5 digit number disivible by 35​

Answer 1

Answer:

the smallest 5 digit number = 10000

when 10000 is divided by 35 the remainder is 25 and 25+10= 35

so the smallest number divisible by 35 will  be 10000+10=10010

Hope it helps u

Answer 2

Given :

Find the smallest 5 digit number that is divisible by 35.

Solution :

The smallest five-digit number = 10000

when we divide this smallest five-digit number by 35, the remainder will be 10

=> 10,000 ÷ 35 = Remainder is 10

=> 10,000 + 10 = 10,010

So, the smallest five-digit number that is divisible by 35 is 10,010.

Hence, The required answer is 10010.