Math, asked by satyamchauhan8503, 1 year ago

Find the smallest 5 digit number divisible by 15 24 and 36

Answers

Answered by nehajaglan
0
factors of 15= 3×5
=3^1×5^1
factors of 24=2×2×2×3
=2^3×3^1
factors of 36=2×2×3×3
=2^2×3^2

LCM= 5^1×3^2×2^3
=5×3×3×2×2×2
= 360

the 5 digit no should be multiple of 360.

smallest 5 digit no = 10000
let divide 10000 by 360 .
r = 280.

10280 is the 5 digit smallest no. divisible by 15,24and36.
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