find the smallest 5_digit number that is divisible by 35
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2
Answer:
10010 is the leastest 5 no. divided by 35.
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5
The smallest 5 digit number = 10000.
The remainder when 10000 divided by 35 = 25 + 10 is 35
Therefore the smallest 5 digit number divisible by 35
= 10000+10 =10010.
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