Question

find the smallest 5 digit number which is divisible by 9, 15 and 18

Answer 1

Answer:

zghz BBS no e n WA nsnNn WA no Sada n seas

Step-by-step explanation:

1ppppppppppppoajanjzjbzbzisnDendjCNN xnxnb

Answer 2

Answer - 10080

• First we have to find the L.C.M of 9, 15 and 18.

• L.C.M = 2×3×3×5 = 90

• Largest 4 digit number divisible by 9, 15 and 18 is; 111×90 = 9990.

• So, Smallest 5 digit no. will be 9990+90 = 10080.

Answer- 10080

Thanks