Question

find the smallest 5 digit number ,which is exactly divisible by 9, 15, 18 .​

Answer 1

Answer:

10080

Step-by-step explanation:

LCM of the divisors= 90

Divide 10000 by 90. We get 111 as the quotient. Ignore the remainder.

111x90= 9990. This is the largest 4 digit number exactly divisible by 9, 15 and 18.

To get the smallest 5 digit number as needed, simply add 90.

We get= 9990+90= 10080

Answer 2

Answer - 10080

• First we have to find the L.C.M of 9, 15 and 18.

• L.C.M = 2×3×3×5 = 90

• Largest 4 digit number divisible by 9, 15 and 18 is; 111×90 = 9990.

• So, Smallest 5 digit no. will be 9990+90 = 10080.

Answer- 10080.