Find the smallest 5- digit number which is exactly divisible by 15, 24 and 40.
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Answer:
Factors of
15 = 3x5
24 = 2x2x2x3
40 = 2x2x2x5
LCM = 2x2x2x3x5 = 120
10000/120 = 83.3
84*120 = 10080.
So 10080 is the smallest 5-digit number divisible by 15, 24 and 40.
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