Question

find the smallest 5-digit number which is exactly divisible by 27,19and48​

Answer 1

step by step explanation:-

Smallest 5 - digit number = 10000,

To find smallest 5 - digit number which is exactly divisible by 27, 19 and 48, we have to find LCM of given numbers first.

19 = 19,

27 = 3*3*3,

48 = 2*2*2*2*3.

LCM = 2*2*2*2*3*3*3*19 = 8208.

10000 can be written as (8208+1792).

So, (8208*2) = 16416 will be the smallest number which is exactly divisible by 19, 27 and 48.

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Answer 2

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