Question

find the smallest 5 digit number which when divided by 16 32 18 24 and 36 leaves remainder 6 in each case answer will 10036 but how explain it​

Answer 1

Answer:

I hope u understand

Step-by-step explanation:

First of all we need to find the LCM of 16, 18 and 32

16=2×2×2×2

18=2×3×3

32=2×2×2×2×2

LCM=16=2×2×2×2×2×3×3=288

288+5=293

293 is the smallest number which leaves a remainder of 5 when

divided by 16, 18 and 19.

check:

293=16×18+5

293=18×16+5

293=32×9+5

Answer 2

Step-by-step explanation:

lcm 432

5 digit smallest number 10000

432÷10000

64=remainder

required number 10000+(432-64)

10000+368

1036 answer