Question

find the smallest 5 digit number which when divided by 25 40 and 60 leaves the remainder 6 in each case​

Answer 1

Answer:

10206 is required answer.

Explaination:

LCM of 25, 40 and 60 is 600.

Smallest 5 digit no. is 10000.

multiple of 600 nearest to 10000 is 10200.

the required number should be=10200+6= 10206 (since the remainder is 6)

Answer 2

Step-by-step explanation:

LCM of 25,40,60 equals to 600

smallest 5 digit number is 10000

Now multiple of 600 nearest to 10000 equal to 10200

Reminder is 6

Hence no is 10200+6=10206