Math, asked by safirahmad0p2wm03, 1 year ago

find the smallest 6 digit number divisible by 22,55 and 110

Answers

Answered by angelurvashi31
9

Answer:

100100

Step-by-step explanation:

First we take L.C.M of 22,55 and 110

L.C.M - 2*11*5 = 110

smallest 6 - digit no. = 100000 then divide 100000 from 110

remainder = 10

100000 minus 10 = 99990

we have 5 - digit no. 99990 + 110

100100 *correct answer*

Answered by dhruvtiwari704
0

Answer:

100100

Step-by-step explanation:

LCM of 22, 55 , 110

Total LCM = 110

110 ÷ smallest 6 digit number

Q = 909 R = 10

100000 - 10 = 99990

To make it 6 digit + LCM

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