Math, asked by sahelisalonbnl4128, 11 months ago

find the smallest 6 digit number.in which when 45 is added its sum is completely divisible by 159

Answers

Answered by SnehaSingh200324

18

Answer:

First, we find the LCM of 48 and 108 = 432
the smallest six digit number = 100000
100000÷432 =
quotient = 231
remainder = 208
the required number = 100000 - remainder + LCM = 100000 - 208 + 432 = 100224.

Step-by-step explanation:

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