Math, asked by hussainbholu786, 9 months ago

Find the smallest 6-digit number that is exactly divisible by 48 and 108? explain with process

Answers

Answered by Anonymous
5

Answer:

Question :-

  • Find the smallest 6-digit number that is exactly divisible by 48 and 108? explain with process

Given :-

  • number that is exactly divisible by 48 and 108

To Find :-

  • Find the smallest 6-digit number

Solution :-

the LCM of 48 and 108 = 432

the smallest six digit number = 100000

100000/432 = quotient = 231

remainder = 208

the required number =100000 - remainder + LCM

100000 - 208 + 432 = 100224.

Hence the smallest 6-digit number is 100224

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