Find the smallest 6-digit number that is exactly divisible by 48 and 108? explain with process
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Question :-
- Find the smallest 6-digit number that is exactly divisible by 48 and 108? explain with process
Given :-
- number that is exactly divisible by 48 and 108
To Find :-
- Find the smallest 6-digit number
Solution :-
the LCM of 48 and 108 = 432
the smallest six digit number = 100000
100000/432 = quotient = 231
remainder = 208
the required number =100000 - remainder + LCM
100000 - 208 + 432 = 100224.
Hence the smallest 6-digit number is 100224
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