Find the smallest 6 digit number which is exactly divisible by 36, 45and 60
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Answer:
The smallest 6 digit number which is exactly divisible by 36, 45and 60 is 100080.
Step-by-step explanation:
The smallest 6 digit number which is exactly divisible by 36, 45and 60.
36=2x2x3x3 = 2^2 x 3^2
45=3x3x5 = 3^2 x 5
60=2x2x3x5 = 2^2 x 3 x 5
LCM (36, 45, 60 ) = 2^2 x 3^2 x 5 = 4 x 9 x 5 =20 x 9 =180
∴ Required smallest 6-digit number which is divisible by 36, 45 and 60
is = 1556 x 180 = 100080
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