Question

Find the smallest and the greatest angle of a pentagon whose angles are in the ratio 6:3:2:5:4 . Please don't spam .​

Answer 1

The angles of a pentagon are in the ratio 4:8:6:4:5.

The angles of a pentagon are in the ratio 4:8:6:4:5. Let angle be 4x, 8x, 6x, 4x and 5x.

The angles of a pentagon are in the ratio 4:8:6:4:5. Let angle be 4x, 8x, 6x, 4x and 5x. Sum of interior angle of a polygon = 180

The angles of a pentagon are in the ratio 4:8:6:4:5. Let angle be 4x, 8x, 6x, 4x and 5x. Sum of interior angle of a polygon = 180 o

The angles of a pentagon are in the ratio 4:8:6:4:5. Let angle be 4x, 8x, 6x, 4x and 5x. Sum of interior angle of a polygon = 180 o (n−2)

The angles of a pentagon are in the ratio 4:8:6:4:5. Let angle be 4x, 8x, 6x, 4x and 5x. Sum of interior angle of a polygon = 180 o (n−2) Sum of interior angle of a pentagon = 180 ,120 o ,80 o and 100 o .

Answer 2

Answer:

Hey friend,

Here is the answer you are searching for,

Number of sides in pentagon = 5

Formula to find sum of all angles in a polygon

= (n-2)180 [where n = number of sides]

Therefore,

Sum of all angles = 3×180 = 540

Let angles be 6x,3x,2x,5x,4x,

=> 6x+3x+2x+5x+4x = 540

=> 20x = 540

=> x = 27

Therefore,

Angles = 162,81,54,135,108

Therefore,

Smallest angle = 54

Greatest angle = 162

HOPE IT HELPS YOU.

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