find the smallest angle of parallelogram if 2 consecutive angle are in the ratio 1:3
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Consecutive angles of a parallelogram are co-interior angles.
Let one angle be L1=x
and
other angle be L2 =3x
L1 +L2 =180°
⇒x+3x=180°
⇒4x=180°
⇒x=45°
hence the smaller angle is 45°
Answered by
0
Step-by-step explanation:
Consecutive angles of a parallelogram are co-interior angles.
Let one angle be L1=x
and
other angle be L2 =3x
L1 +L2 =180°
⇒x+3x=180°
⇒4x=180°
⇒x=45°
hence the smaller angle is 45°
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