Question

Find the smallest divisible by 15.20.24.32and36

Answer 1

the smallest no. divisible by any two or more numbers is the L.C.M. of all those numbers.

therefore, taking the LCM of 15,20,24,32,and 36

2*2*2*2*2*3*3*5*5= 7200

so 7200 is the required number.