Question

find the smallest five digit no that exactly divided by 60,80and 90​

Answer 1

Answer:

What is the smallest number of five digits that can be exactly divided by 60, 80, and 90?

For such types of questions you must know how to get lowest common multiple of numbers i.e. LCM and i am assuming that you know it.

So LCM (60, 80, 90) will be 720.

And for lowest five digit number you should take largest four digit number(i.e. 9999) …..and if the case would be of highest five digit number you should take lowest six digit number(i.e. 100000) …..remember it

Now divide the number by the LCM

9999÷720 THEN remainder will be 639

Take difference of (720–639) = 81

Add it in largest 4 digit number ….9999+81 = 10080 will be your answer.

Im case of highest five digit number ….

Divide 100000 by 720 then remainder will be 640

Now in this case you have to subtract this remainder from the largest 6 digit number ..

100000–640 = 99360 will be your largest five digit number divisible by 60, 80 and 90.

Step-by-step explanation:

Hope it helps

Answer 2

Step-by-step explanation:

Ans:A number which is exactly divided by 60,80 and 90 is also divided by their LCM

The LCM of 60,80and90is:720

The smallest five digits number(10000)is not divided by the LCM (Lowest Common Multiple) of60,80and90.

So,divide the greatest five digits number 99999 by the LCM 720

On dividing 99999 by720,we get quotient138 and remainder 639

Now subtract the remainder 639 from 99999

99999–639=99360,which is divisible by 720

Thus,the required smallest five digits number which is exactly divided by60,80and90is