Math, asked by gw013112, 9 months ago

Find the smallest five digit number that can be exactly divisible by 21 ,28, 36 and 45

Answers

Answered by varshitha1934
0

Answer:

Step-by-step explanation:

The smallest 5 digit number is 10000

Answered by ranaabhi1103
0

Answer:

Step-by-step explanation:

TO GET THAT NUMBER WE HAVE TO DO LCM OF 21,28,36,AND 45

OK

SO THE LCM OF 21, 28, 36, AND 45 IS : (I AM TELLING THE LCM THROUGH PRIME FACTORIZATION METHOD )

21 = 3 × 7

28 = 2 × 2 × 7

36 = 2 × 2 × 3 × 3

45 = 3 × 3 × 5

LCM = 2² × 3² × 5 × 7

= 1260

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