Find the smallest five digit number that can be exactly divisible by 21 ,28, 36 and 45
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Answered by
0
Answer:
Step-by-step explanation:
The smallest 5 digit number is 10000
Answered by
0
Answer:
Step-by-step explanation:
TO GET THAT NUMBER WE HAVE TO DO LCM OF 21,28,36,AND 45
OK
SO THE LCM OF 21, 28, 36, AND 45 IS : (I AM TELLING THE LCM THROUGH PRIME FACTORIZATION METHOD )
21 = 3 × 7
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
45 = 3 × 3 × 5
LCM = 2² × 3² × 5 × 7
= 1260
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