Question

find the smallest five-digit number which is exactly divisible by 32;36;40;45 and 48​

Answer 1

Answer:

Step-by-step explanation:

Answer: The required number is 10080 which is exactly divisible by 32,36 and 45.

Answer 2

$\underline\mathtt\red{QuEsTiOn::}$ A,B,C and D are four-digit numbers in which 9occues only once and ot's place is :. A` (9) [] [] []

B` [] 9 [] []

C` [] [] 9 []

D` [] [] [] 9

Nothing is known about the rest digits.

What can you say about numbers A,B,C AND D?

1. Cis the smallest of all four numbers!

2. B is smaller than C!

3. A is the greatest of all numbers!

4. D is the greatest of all numbers!

$ANSWERCORRECTLY\underline\mathtt\red{QuEsTiOn::}$