Question

Find the smallest five digit number which when divided by 15,20,30 and 35 leaves remainder 5 in each case​

Answer 1

Step-by-step explanation:

first we have to find the LCM of 152030 and 35

LCM = 2520

but it is not a five digit no . so we will multiply it with 2 till we get a five digit no .

2520×2=5040

5040×2=10080

no. 10080 is the smart no by which can be divided by each no.

but it says that remainder is 5 in each case so we will add 5 to it

10080+5=10085

ans =10085

Answer 2

The smallest digit which leaves the remainder is 425

Given:

The digits 15,20,30 and 35 leaves the remainder 5

To Find :

The digit which leaves the remainder 5 from the following

Solution:

Taking LCM for  15,20,30 and 35

15 = 3 ×5

20 = 4×5

30 = 6×5

35 = 7×5

Total LCM is equal to = 420

Then, the number 5 leaves the remainder ,

So, it becomes 420+5 = 425

The number which leaves the remainder is 425

#SPJ2