Question

find the smallest five digit number which when divided by 15, 20, 30 and 35 leaves remainder 5 in each case?​

Answer 1

Step-by-step explanation:

$\huge\sf\underline{\underline{\pink{✤ Question:-}}}$

find the smallest five digit number which when divided by 15, 20, 30 and 35 leaves remainder 5 in each case?

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1)LCM of 15 , 20 , 30 , 35

2) multiplying the LCM of 15 , 20 , 30 , 35 by 2 until it is 5 digit no

3) adding the answer which is divided by 5

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LCM of 15,20,30,35 =5[15,20,30,35]

2[3,4,6,7]

2[3,2,3,7]

3[3,1,3,7]

7[1,1,1,7]

1[1,1,1,1]

=5×2×2×3×7

=1,260

LCM of 15,20,30,35=1,260

multiplying the LCM of 15 , 20 , 30 , 35 by 2 until it is 5 digit no= 1260×2

=2520×2

=5040×2

=10,080

adding the answer which is multiply by 5

=10080+5

=10085

$\huge{\underline{\purple{★check:-}}}$

10,080÷20=504

10080÷15=672

10080÷30=336

10080÷35=288

hence answer is verified