Question

find the smallest five digit number which when divided by 15,20,30and35 leaves remainder 5 in each case?

Answer 1

5 is divided by these no.

Answer 2

Here we have to find the LCM of 15,20,30and 35

15=3×5
20=2×2×5
30=2×3×5
35=5×7

LCM=5×2×2×2×3×3×7
=2520
But it is not a five digit number

So , we will.multiply ig with 2 till we get a five digit number:-

=2520×2=5040
=5040×2=10080

Now 10080 is the smallest five digit number which can divided be each number .

But it is given that each number will leave a remainder of 5

So the required number = 10080 + 5 = 10085

Answer :- The required number is 10085

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