Math, asked by riyay8081, 7 months ago

find the smallest five digit number which when divided by 16 32 18 24 and 36 leaves remainder 6 in each case

Answers

Answered by dheeraj26singh

5

First find the LCM of 16,24,36 and 54.

LCM=432.

Smallest 5 - digit no.=10000

Divide 10000 by 432.

Remainder=64

Req. no. = 10000+(432-64)

=10000+368

=10368

Ans.=10368 is the smallest 5 digit no. exactly divisible by 16,24,36 and 54.

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