Question

Find the smallest five digit number which when divided by 16,18,24and 32 leaves remain der 6 in each case​

Answer 1

Answer:

Step-by-step explanation:

First find the LCM of 16,24,36 and 54.

LCM=432.

Smallest 5 - digit no.=10000

Divide 10000 by 432.

Remainder=64

Req. no. = 10000+(432-64)

            =10000+368

            =10368

Ans.=10368 is the smallest 5 digit no. exactly divisible by 16,24,36 and 54.