Find the smallest five digit number which when divisible by 15 20 30 and 35 leaves remainder 5 in each case
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So,LCM(15,20,35)=2^2 × 3×5×7 =420. Hence,required number =420+5 =425 Ans .
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Answer:
So,LCM(15,20,35)=2^2 × 3×5×7 =420. Hence,required number =420+5 =425 Ans .
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