find the smallest four digit number exactly divisible by 18, 24 and 32
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The smallest 4-digit number which is divisible by 18, 24 and 32., will be simply the 4 digit number necessarily a multiple of LCM of the given numbers i.e. 18, 24 and 32.
LCM of 18, 24 and 32= 2 ×2 ×2 ×2 ×2 ×3×3× = 288
required smallest 4-digit number which is divisible by 18, 24 and 32
number is = 4 × 288 = 1152
LCM of 18, 24 and 32= 2 ×2 ×2 ×2 ×2 ×3×3× = 288
required smallest 4-digit number which is divisible by 18, 24 and 32
number is = 4 × 288 = 1152
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