Find the smallest four-digit number which is divisible by 18, 24 and 32 a) 1152 b) 1288 c) 1136
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28
Answer:
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The smallest four-digit number which is divisible by 18, 24 and 32 is 1152 . (option a. )
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Answered by
5
Answer:
LCM of 18, 24 and 32
18 = 2*3*3
24= 2*2*2*3
32=2*2*2*2*2
LCM = 2*2*2*2*2*3*3
= 288
Since it has to be a 4 digit number
288*2= 576
288*3= 864
288*4= 1152
Answer is a) 1152
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