Find the smallest four digit number which is exactly divisible by 10,12 and 14
Answers
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I’ll go through a step by step, as detailed as possible path on solving this problem, and the algorithm can be applied in any similar case.
- Let’s do prime factorization for the three numbers to find the least common multiple (LCM) for the given numbers:
8 = 2 * 2 * 2
10 = 2 * 5
12 = 2 * 2 * 3
- As far as 3 and 5 are odd numbers, we’ll have the following to construct the LCM for the three numbers:
2*2*2, the number’s divisible by 8
2*2*2*5 will make the number divisible by 10 (LCM for 8 and 10)
2*2*2*5*3 the number’s now divisible by 12 (LCM for 8, 10, 12)
So we have 2*2*2*3*5 = 120 and it’s the LCM of 8, 10 and 12.
- The smallest four digit number is 1000, right? :)
So now we have to find the smallest four digit number that is a multiple of 120, let’s go:
a)
1000 / 120 = 8.33
8 < 8.333 < 9
8 * 120 = 960 (it is not a four digit number)
9 * 120 = 1080 (or 960 +120) which is a four digit number and it’s the smallest four digit number which is divisible by 8, 10 and 12.
OR
b)
1000 / 120 = 8 (remainder = 40)
1000 + 120 - 40 = 1080