Question

Find the smallest length of a rope which can be measured in exact number
of times by three tapes measuring 1 m 20 cm, 75 cm and 1 m respectively.
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Answer 1

Answer:

We need to find hcf of 1m20cm= 120cm, 75cm, 1m= 100cm.

120= 2*2*2*3*5

75=3*5*5

100= 2*2*5*5

Hcf= 5

Lenght of rope = 5cm