Question

find the smallest natural no which when divided by 16,24,40 leaves a remainder 8 in each case

Answer 1

First find the LCM of 16, 24 and 40 
That is = 240 
( 8 × 2 × 3 × 5 = 240) 
Remainder = 8 
= 240 + 8 = 248 Answer 
= 248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder, 8. 

example= 248 ÷ 16 = 
Q = 15 and 
R = 8 . 

Hope, I helped you.

Answer 2

Answer:

First, we factorize

16 = 2×2×2×2

24 = 2×2×2×3

40 = 2×2×2×5

The smallest number divisible by 16, 24, 40 is

LCM(16, 24, 40) = 240

Thus to get 8 as remainder, we need 8 to 240 ( as 240 is the smallest number which gives the remainder 0 when it is divided by 16, 24, 40 )

So 240 + 8 =248

∴ 248 is the smallest natural number which is divided by 16, 24, 40 leaves a remainder 8.