find the smallest natural no which when divided by 16,24,40 leaves a remainder 8 in each case
Answers
Answered by
0
First find the LCM of 16, 24 and 40
That is = 240
( 8 × 2 × 3 × 5 = 240)
Remainder = 8
= 240 + 8 = 248 Answer
= 248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder, 8.
example= 248 ÷ 16 =
Q = 15 and
R = 8 .
Hope, I helped you.
That is = 240
( 8 × 2 × 3 × 5 = 240)
Remainder = 8
= 240 + 8 = 248 Answer
= 248 is the smallest number which when divided by 16, 24 and 40 leaves the remainder, 8.
example= 248 ÷ 16 =
Q = 15 and
R = 8 .
Hope, I helped you.
Similar questions