Find the smallest natural number p such that p is divisible by 330
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Answer:
330
Step-by-step explanation:
We need to find the smallest natural number p such that p is divisible by 330.
If p is divisible by 330, it means 330 is a factor of p.
.... (1)
where, n can be any integer.
It is given that p is a natural number, so the value of n in p=330n must be greater than 0.
Substitute n=1 in equation (1), to find the smallest natural number p which is divisible by 330.
Therefore the value of p is 330.
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